Tonight I have my second Calculus 2 test for the
semester, and if you've been reading this for any
period of time then you've heard me
Right here we have the problem>>>
y=x^3 from 0 to 2
What we are looking for is the surface area of this curve if you were to rotate it around the X axis on an interval from 0 to 2.
y=x^3 from 0 to 2
What we are looking for is the surface area of this curve if you were to rotate it around the X axis on an interval from 0 to 2.
Isn't this fun already?
<
Still with me?
This is the formula we use to work it out>>>
<<
Look...all done.>>>
approximately 203.0436
6 comments:
oowww! my head hurts.
ew gross
hmm my comment didn't post the first time, so here we go again:
hahahaha, that brings back fond memories. :-P I remember those days. You should see my spacecraft dynamics & control notes.
WHY!!!
not okay! did you create this while you were supposed to be studying last night? oooooo.... i'm telling!
sure, no problem! oh man, calculus. it is my choice whether to take this instead of a science credit...from my AP knowledge in high school I recognize some derivatives... but that's about it. good luck.
I am so glad that part of things is over for me.
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